谁有2011咸阳三模答案、急求、答:(6分) 事实上,点T(1,0)就是所求的点.证明如下:当直线l垂直于x轴时,以AB为直径的圆过点T(1,0).若直线l不垂直于x轴,可设直线l:y=k(x+ ).由即(k2+2)x2+ k2x+ k2-2=0.记点A(x1,y1),B(x2,y2),则………(9分)又因为 =(x1-1, y1), =(x2-1, y2), • =(x1-1)(x2-1...
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