设计程序求一维数组a[6]= {1,0,7,4,3,6}之和及元素中的最大值,并将和...答:include<stdio.h> int main(){ int a[6]={1,0,7,4,3,6},s=0,max=-999;for(i=0;i<6;i++){ s+=a[i];if(max
求一维数组A中值为奇数的元素之和答:include <conio.h> include <stdio.h> int sum( int b[ ],int n ){ int i,s = 0;for ( i=0; i<n; i++)if (b[i] % 2 == 1)s = s + b[i]return (s);} main(){ int a[12]={10,4,2,7,3,12,5,34,5,9,21,19},n;clrscr();n = sum(a,12);//这里应该...
C#的,求一维数组中各元素的偶数之和。答:步骤:一、循环遍历数组中每一个元素 二、判断是否为偶数,若是,则相加 代码:int i = 0;int [] array = {1,2,3,4,5,6,7,8,9,10};int sum = 0;for(i = 0;i < array.Length;i ++){ if(array[i] % 2 ==0){ sum = sum + array[i];} } ...
C++中怎么用指针变量求一个一维数组中所有元素的最大值和平均值?答:main(){ int a[]={1,2,3,5,4},max,*p=&max;float av,*q=&av;void f(int a[],int *p,float *q);f(a,p,q);printf("max=%d\nav=%f\n",max,av);}
定义一个函数求一维数组中两个元素的和,具体怎么写啊,急答:include<stdio.h>#define N 10int msum(int *a,int n1,int n2) { int x; x=a[n1]+a[n2]; return x; }void main() { int a[N],i,n1,n2,s; for ( i=0;i<N;i++ ) scanf("%d",&a[i]); scanf("%d%d",&n1,&n2); s=msum(a,n1,n2); printf("a[%d]+a[...