请用C语言:求一个数组中所有元素的和,在主函数中检验答:200,300,400,500,600,700,800,900,1000},i,sum=0; char nums2str[10][5]={"100","200","300","400","500","600","700","800","900","1000"},str[41]; printf("数字型和字符串型的两个数组元素分别为:\n"); ...
...二维数组a[3][4]={1,2,3,4,5,6,7,8,9,10,11,12},求出所有元素...答:public static void main(String[] args) { Integer[] num={1,2,3,4,5,6,7,8,9,10,11,12};int sum=0;for(int i=0;i<num.length;i++){ sum+=num[i];} int avg=sum/num.length;for(int i=0;i<num.length;i++){ if(num[i]>avg){ System.out.println(num[i]+" 下标...
设计一个算法,求一维数组float a[n]中所有元素之和,写出相应C程序...答:int i = 0;//...for( i = 0,result=0; i < n; i++){ result += a[i];} include <stdio.h> int main(){ int n = 10;int i = 0;float a[10] = {1,2,3.4,5.5,2.3,1.2,1.6,7,8,12.12};float result = 0;for (i = 0, result = 0; i < n; i++)...