Python列表求最大值答:>>> a = [[4,2,5,7,6,3],[5,8,3,4,9,0]]>>> b=[[each.index(max(each))+1,max(each)] for each in a]>>> b[[4, 7], [5, 9]]>>>
python循环输入若干个同学的成绩,求出这些同学的成绩平均值、最小值和...答:最大值和最小值可以用max(),min()include <iostream> using namespace std;int main(){ int score[] = {78, 86, 90, 83, 74, 68, 74, 80, 69, 79, 89, 93};int n = 12;int min, max;double avg;int i;min = max = score[0];avg = 0;for(i=0; i<n; i++)baiavg...