SQL 日期格式转换答:select substring('20090826132252',1,4)+'-'+substring('20090826132252',5,2)+'-'+substring('20090826132252',7,2)+' '+substring('20090826132252',9,2)+':'+substring('20090826132252',11,2)+':'+substring('20090826132252',13,2)以上转换后为varchar类型的 select cast(substring('...