已知函数f(x)=x|x+2|,求函数的单调区间答:令g(x)=x,m(x)=|x+2|,则g(x)在[负无穷,正无穷]是单调增的,m(x)在[负无穷,-2]上单调减,在[-2,正无穷]单调增,故f(x)=g(x)m(x)在[负无穷,-2]上单调减,在[-2,正无穷]单调增
f(x)是奇函数,f(x+2)=f(x)当x属于[0,1]时,fx=x^2 当x属于[2011,2013]时...答:f(x+2)=f(x)T=2 当x属于[0,1]时,fx=x^2 当x属于[-1,0]时,fx=-f(-x)=-x^2 [2011,2013]=[-1,1]=[-1,0]+[0,1]f(x)=x^2 [2012,2013]f(x)=-x^2 [2011,2012]