已知一个整形数组[3,7,8,9,10,4,5],求该数组中所有值为偶数的元答:include <stdio.h>int main(){ int a[7] = { 3,7,8,9,10,4,5 }; int i,s = 0; for( i = 0; i < 7; ++i){ if( a[i] % 2 == 0 ) s += a[i]; } printf("%d\n",s); return 0; } ...
一个数组有10 个元素{1,8,10,2,-5,0,7,15,4, -5}, 利用指针作为函数参 ...答:include<stdio.h>void maxmin(int* a,int*min,int*max){ int i; *min=*max=*a; for(i=1;i<10;i++) { if(*min>*(a+i)) *min=*(a+i); if(*max<*(a+i)) *max=*(a+i); }}void main(){ int a[10]={1,8,10,2,-5,0,7,15,4, -5}...