00问答网
所有问题
(x-1)(x+1)(x+3)(x+5)+1 因式分解 快 因式分解
如题所述
举报该问题
其他回答
第1个回答 2020-03-15
(x-1)(x+1)(x+3)(x+5)+1
=(x^2+4x+5)(x^2+4x+3)+1
=(x^2+4x)^2+8(x^2+4x)+15+1
=(x^2+4x)^2+8(x^2+4x)+16
=(x^2+4x+4)^2
=(x+2)^4
相似回答
(x-1)(x+1)(x+3)(x+5)+1
因式分解
答:
解:原试=
(X-1)(X+5)(X+1)(X+3)+1
=(X^2+4X-5)(X^2+4X+3)+1 =(X^2+4x)^2-2(x^2+4x)-14 =(x^2+4x-1)^2-15 =(x^2+4x-1+根号15)(X^2+4X-1-根号15)
因式分解
(x-1)(x+1)(x+3)(x+5)+
15
答:
解:(1)
(x-1)(x+1)(x+3)(x+5)+
15=[(x-1)(x+5)][(x+1)(x+3)]+15 =(x²+4x-5)(x²+4x+3)+15 =(x²+4x)²-2(x²+4x)-15+15 =(x²+4x)[(x²+4x)-2]=(x²+4x)(x²+4x-2)=x(x+4)[(x+2)²...
把
(x-1)(x+3)+5
因式分解
答:
因式分解
:
(x-1)(x+1)(x+3)(x+5)+
16 解:(x+1)(x-1)(x+3)(x+5)+16 =(x+1)(x+3)(x-1)(x+5)+16 =(xx+4x+3)(xx+4x-5)+16 =(xx+4x)^2-2(xx+4x)-15+16 =(xx+4x)^2-2(xx+4x
)+1
=(xx+4x-1)^2 注:(x+1)(x+3)=xx+4x+3 (x-1)(x+5)=xx+...
因式分解
:
(x-1)(x+1)(x+3)(x+5)+
16
答:
解:
(x+1)(x-1)(
x+3)(x+5)+16 =(x+1)(x+3)(x-1)(x+5)+16 =(xx+4x+3)(xx+4x-5)+16 =(xx+4x)^2-2(xx+4x)-15+16 =(xx+4x)^2-2(xx+4x)+1=(xx+4x-1)^2 注:(x+1)(x+3)=xx+4x+3 (x-1)(x+5)=xx+4x-5 ...
大家正在搜
分解因式和因式分解的区别
x^3-3x+2因式分解
因式分解x²+x+1
x^2+x+1因式分解
x∧3+1因式分解
1-x3因式分解
1-x^3因式分解
x³-1因式分解
1+x^4因式分解