建立一个用户图形界面 1，用菜单实现sinx/x和sinx的图形显示 2，利用快捷菜单实现对图形线型颜色及属性的处理 3，在曲线最大处标记函数名 我自已写的程序如下 screen=get(0,'ScreenSize'); W=screen(3);H=screen(4); %定义菜单选项，绘曲线 figure('Color',[1,1,1],'Position',[0.4*H,0.4*H,0.8*W,0.6*H],'Name',... '显示函数图形','NumberTitle','off','MenuBar','none'); hplot=uimenu(gcf,'Label','绘曲线'); uimenu(hplot,'Label','sinx/x','Call',['x=0:pi/100:2*pi;y=sin(x)./x;line=plot(x,y);']); uimenu(hplot,'Label','sinx','Call',['x=0:pi/100:2*pi;y=sin(x);line=plot(x,y);']); %定义快捷菜单，实现对图形线型颜色及属性的处理 jhf=uicontextmenu; xx=uimenu(jhf,'Label','线型'); xk=uimenu(jhf,'Label','线宽'); ys=uimenu(jhf,'Label','颜色'); uimenu(xx,'Label','虚线','Call',['set(line,''LineStyle'','':'');']); uimenu(xx,'Label','实线','Call',['set(line,''LineStyle'',''-'');']); uimenu(xx,'Label','点划线','Call',['set(line,''LineStyle'',''-.'');']); uimenu(xx,'Label','双划线','Call',['set(line,''LineStyle'',''--'');']); uimenu(xk,'Label','宽','Call',['set(line,''LineWidth'',5);']); uimenu(xk,'Label','窄','Call',['set(line,''LineWidth'',0.5);']); uimenu(ys,'Label','蓝色','Call',['set(line,''Color'',''b'');']); uimenu(ys,'Label','绿色','Call',['set(line,''Color'',''g'');']); uimenu(ys,'Label','红色','Call',['set(line,''Color'',''r'');']); uimenu(ys,'Label','青色','Call',['set(line,''LineColor'',''c'');']); uimenu(ys,'Label','品红色','Call',['set(line,''Color'',''m'');']); uimenu(ys,'Label','黄色','Call',['set(line,''Color'',''y'');']); uimenu(ys,'Label','黑色','Call',['set(line,''Color'',''k'');']); uimenu(ys,'Label','白色','Call',['set(line,''Color'',''w'');']); set(line,'UIContextMenu',jhf); %用按钮来实现标记 jhf1=uicontrol(gcf,'Style','push','Position',[20,20,100,25],'String','显示函数','Callback',... ['my=max(line);a=find(my);mx=(a+1)*pi/100;text(mx,my,'y=sinx/x y=sinx')']; 但是快捷菜单是在窗口中，用菜单画出曲线之后就没有快捷菜单了 该怎么改？谢谢~~