从键盘输入一个字符串，统计输出其中’a’的个数，并把字符串中所有的a替换为b，然后输出替换后的字符串。

Question

用C语言

Answer 1

#include <stdio.h>
#include <string.h>
int main(int argc, char *argv[])
{
char s[1000];
int i,count=0;
gets(s);
for(i=0;s[i]!='\0';i++)
if(s[i]=='a'){
s[i]='b';
count++;
}
printf("a有%d个\n",count);
puts(s);
return 0;
}本回答被提问者采纳

Answer 2

#include <stdio.h>
#define N 100

int change(char *s)
{
int sum=0,i=0;
while(s[i]!='\0')
{
if(s[i]=='a')
{
sum++;
s[i]='b';
}
i++;
}
return sum;
}

void main()
{
char s[N];
int count;
printf("Please input a string:");
scanf("%s",s);
printf("The src's string is \"%s\"\n",s);
count=change(s);
printf("The number of 'a' is %d\n",count);
printf("The tar's string is \"%s\"\n",s);

}