编程，求2+4+6+8+...+100的值并显示出来。

Question

c语言

Answer 1

#include<stdio.h>void main() { int i; int sum=0; for(i=1;i<=100;i=i++) {if(i%2==0) sum=sum+i; } printf("2+4+6+...100=%d\n",sum); }

Answer 2

#include <stdio.h>
int main()
{
int i;
int sum=0;
for(i=2;i<=100;i=i+2)
{
sum+=i;
}

printf("2+4+6+...100=%d\n",sum);

}

Answer 3

int i,sum=0;for(i=2;i<=100;i=i+2){ sum=sum+i;}

Answer 4

你没说出语言，给你个VB代码：
s=0

for i=2 to 100 step 2
s=s+i
next i
print s

Answer 5

var s,i:longint;
begin
s:=0;
for i:=1 to 100 do
if i mod 2=0 then
s:=s+i;
writeln(s);
end.