分解因式：x平方-2xy+y平方-2x+2y+1

Question

如题所述

Answer 1

原式=(x-y)²-2(x-y)+1
=(x-y-1)²本回答被提问者采纳

Answer 2

x²-2xy+y²-2(x-y)+1
(x-y)²-2(x-y)+1
[(x-y)-1]²

Answer 3

x平方-2xy+y平方-2x+2y+1=(X-Y)^2-2(x-Y)+1=(X-Y+-1)^2

Answer 4

（x-y）平方-2（x-y）+1
=（x-y-1)平方

Answer 5

（-x+y+1)^2