用C++编程用while循环，要求求e的值，e约等于1+1/1!+1/2!+1/3!+......+1/N! 要求直至最后一项的值小于10^-

Question

如题所述

Answer 1

#include<stdio.h>
void main()
{
double b=1,a=1,n,i,j=1;
while(a>=1e-7)
{
n=1;
i=1;
while(i<=j)
{
n=n*i;
i++;
}
a=1/n;
b=a+b;
j++;
}
printf("%f\n",b);
}
看不清楚你写的是小于10的几次方，我这是小于10的-7次方

Answer 2

楼主是中财金工的吧

Answer 3

#define loop 100
#define accuracy 1.0/10
void main()
{
int n,i;
double e,t,term;
e=1;
n=1;
while(n<=loop)
{
for(t=1,i=1;i<=n;i++)
t=t*i;
term=1.0/t;
e+=term;
if(term<accuracy)
break;
n++;
}
if(n>loop)
{
cout<<"\nFinal value of loop is not sufficient.\n";
return;
}
cout<<e<<endl;
}本回答被提问者和网友采纳