x的5次方+x的4次方+1因式分解得

Question

x的5次方+x的4次方+1因式分解得
A.(x的2次方+x+1)(X的3次方+x+1) B.(X的2次方-x+1)(X的3次方+x+1)
C.(x的2次方+x+1)(x的3次方-x+1) D.(x的2次方-x+1)(X的3次方-x+1)

求详细过程~

Answer 1

x^5+x^4+1
=x^3(x^2+x+1)-(x^3-1)
=x^3(x^2+x+1)-(x-1)(x^2+x+1)
=(x^3-x+1)(x^2+x+1)
选C、

详见http://zhidao.baidu.com/question/11124088.html本回答被提问者采纳

Answer 2

原式=x^5+x^4+x³-x³+1
=x³(x²+x+1)-(x³-1)
=x³(x²+x+1)-(x-1)(x²+x+1)
=(x²+x+1)(x³-x+1)
选C

Answer 3

x^5+x^4+1
=x^3(x^2+x+1)-(x^3-1)
=x^3(x^2+x+1)-(x-1)(x^2+x+1)
=(x^3-x+1)(x^2+x+1)

C