急！！！！！1+X的五次方等于0。02，求X

Question

是1+X的五次方等于1。2，求X

Answer 1

>> syms x
>> f=(1+x)^5-1.2

f =

(1+x)^5-6/5

>> solve(f,x)

ans =

[ 1/5*6^(1/5)*5^(4/5)-1]
[ 1/5*(1/4*5^(1/2)-1/4+1/4*i*2^(1/2)*(5+5^(1/2))^(1/2))*6^(1/5)*5^(4/5)-1]
[ 1/5*(-1/4*5^(1/2)-1/4+1/4*i*2^(1/2)*(5-5^(1/2))^(1/2))*6^(1/5)*5^(4/5)-1]
[ 1/5*(-1/4*5^(1/2)-1/4-1/4*i*2^(1/2)*(5-5^(1/2))^(1/2))*6^(1/5)*5^(4/5)-1]
[ 1/5*(1/4*5^(1/2)-1/4-1/4*i*2^(1/2)*(5+5^(1/2))^(1/2))*6^(1/5)*5^(4/5)-1]
>> double(S)

ans =

0.0371
-0.6795 + 0.9864i
-1.8391 + 0.6096i
-1.8391 - 0.6096i
-0.6795 - 0.9864i

Answer 2

看楼上的答案吧，ans=的后部分，应该错不了 ，matlab很强大