设ç´çº¿ä¸ºy=k(x+2)+2
x=0æ¶ï¼y=2k+2
y=0æ¶ï¼x=-2/k-2
é¢ç§¯=1/2*|(2k+2)(-2/k-2)|=2|(k+1)(1/k+1)|=2|2+k+1/k|=1
æ以æ|2+k+1/k|=1/2
å 为æ|k+1/k|>=2, æ以åªè½ä¸º2+k+1/k=-1/2,
å¾ï¼k+1/k+5/2=0
解å¾k=1/2æ2
æ以ç´çº¿lçæ¹ç¨ä¸ºï¼y=1/2(x+2)+2, æy=2(x+2)+2
å³y=x/2+3, æy=2x+6
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