如题所述
(1,3,6)→t=1
x'(t)=1 y'(t)=6t z'(t)=18t²
(1,3,6)处的切线方程为:
(x-1)/1=(y-3)/6=(z-6)/18
(1,3,6)处法平面方程为:
1·(x-1)+6(y-3)+18(z-6)=0