4(x+3)²=25(x-2)²
4(x+3)²-25(x-2)²=0
[2(x+3)]²-[5(x-2)]²=0
[2(x+3)+5(x-2)][2(x+3)-5(x-2)]=0
[2x+6+5x-10][2x+6-5x+10]=0
[7x-4][16-3x]=0
x1=4/7
x2=16/3
(1+√2)x²-(1-√2)x=0
x[(1+√2)x-(1-√2)]=0
x1=0
x2=(1-√2)/(1+√2)=[(1-√2)(√2-1)]/[(√2+1)(√2-1)]=2√2-3
追问回答的很好了,可惜不是最快的,谢谢!!