用C语言编写“读取一个给定的文本文件，并将文件的内容显示在屏幕上”的一个程序，用vc++6.0运行，谢谢各

Question

如题所述

Answer 1

/*楼上的题目会误人子弟的，这样肯定没法过关，下面的才可以！*/
#include <stdio.h>
#include <stdlib.h>
#include <string.h>

#define szBUF 256

int main(int argc, char * argv[])
{
char filename[szBUF], buf[szBUF]; int r = 0; FILE * f = 0;
if(argc < 2) {
printf("please input the file name:");
gets(filename);
}else
strcpy(filename, argv[1]);
//end if
f = fopen(filename, "r");
if(!f) {
printf("file %s open fault!\n", filename);
return 0;
}//end if
while(!feof(f)) {
r = fread(buf, sizeof(char), szBUF, f);
if(r < 1) break;
fwrite(buf, sizeof(char), r, stdout);
}//end while
fclose(f);
system("pause");
return 0;
}

Answer 2

#include <iostream>
using namespace std;

int main() {
freopen("text.txt","r",stdin);
char str[1024];
cin >> str;
cout << str;
system("pause");
return 0;
}

简单可行……

Answer 3

#include <stdio.h>
#include <stdlib.h>

void main ( void )
{
char fileName[] = "file_to_be_read.txt";
char cmd[1024];
sprintf ( cmd, "type \"%s\"", fileName );
system ( cmd );
}