一题数学求解要详细过程最好写纸上拍过来谢谢了啊计算机摁不出来最好手算那种

Question

如题所述

Answer 1

如图

Answer 2

sin(arcsin1/2+arccos1/3)
=sin（arcsin1/2）cos(arccos1/3)+cos(arcsin1/2)sin(arccos1/3)
=1/2*1/3+根号（1-(1/2)^2）*根号（1-（1/3)^2）
=1/6+（根号3）/2*2根号（2）/3
=1/6+(根号6)/3
=(1+2根号6）/6本回答被网友采纳

Answer 3

解: sin(arcsin1/2+arccos1/3)

=sin(arcsin1/2)cos(arccos1/3)+cos(arcsin1/2)sin(arccos1/3)

=1/2*1/3+√[1-(1/2)^2]*√[1--(1/3)^2]

=1/6+√3/2*(2√2)/3

=(1+2√6)/6

Answer 4

首先你要知道cos θ=1/3=sin（π/2-θ）
所以arccos1/3=θ=π/2-arcsin(1/3)
因此sin(acrsin1/2 + arccos1/3)
=1/2 + π/2 - arcsin(1/3)