直径AB=√[(x1-x2)²+(y1-y2)²];圆心坐标为((x1+x2)/2,(y1+y2)/2);
设半径为r,则r²=(x1-x2)²/4+(y1-y2)²/4 。
则圆的方程为:[x-(x1+x2)/2]²+[y-(y1+y2)/2]²=(x1-x2)²/4+(y1-y2)²/4 。
→x²-(x1+x2)x+(x1+x2)²/4+y²-(y1+y2)y+(y1+y2)²/4=(x1-x2)²/4+(y1-y2)²/4
→x²-(x1+x2)x+x1x2+y²-(y1+y2)y+y1y2=0
→(x-x1)(x-x2)+(y-y1)(y-y2)=0 。
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