(x+y)^2(x-y)^2-(x-y)(x+y)(x^2+y^2)分解因式

Question

如题所述

Answer 1

原式=(x+y)(x-y)[(x+y)(x-y)-(x²+y²)]
=(x+y)(x-y)(x²-y²-x²-y²)
=-2y²(x+y)(x-y)

Answer 2

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Answer 3

原式=(x+y)(x-y)[(x+y)(x-y)-(x²+y²)]
=(x+y)(x-y)[x²-y²-x²-y²]
=-y²(x+y)(x-y)