解1ç±y=2x/x²+1
=2/(x+1/x)
ç¥æ±å½æ°y=2x/x²+1çæ大å¼
å³æ±t=x+1/xçæå°å¼
ç±t=x+1/xâ¥2âxÃ1/x=2
å³x+1/xâ¥2...................å½ä¸ä»
å½x=1æ¶çå·æç«ã
å³1/(x+1/x)â¤1/2
ç¥2/(x+1/x)â¤1
å³yâ¤1
æ
å½æ°y=2x/x²+1çæ大å¼ä¸º1ï¼
2ç±
y=1/x+1/(1-x)
=[1/x+1/(1-x)]Ã1
=[1/x+1/(1-x)]Ã[x+(1-x)]
=1+1+x/(1-x)+(1-x)/x
â¥2+2âx/(1-x)Ã(1-x)/x
=2+2
=4.............å½ä¸ä»
å½x=1/2æ¶çå·æç«
æ
å½æ°y=1/x+1/1-xçæå°å¼ä¸º4.
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