解ï¼è®¾S(x)=â[(-1)^(n+1)][x^(2n+1)]/(2n+1)ï¼n=0,1,2ï¼â¦â¦ï¼âãæå¾ï¼S(x)çæ¶æåºé´ä¸ºä¸¨x丨<1ã
å½ä¸¨x丨<1æ¶ï¼S'(x)=â[(-1)^(n+1)]x^(2n)=-1/(1+x²)ãâ´S(x)=â«(0,x)S'(x)dx=-arctanxï¼å
¶ä¸xâ[-1,1]ã
ä¾åèã
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