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iL(0)=((12/6)=2A
iL(â)=(2/3)[12/(4+4//2)]=(2/3)12/(32/6)=(2/3)(72/32)=3/2A
Ï=L/R=2/(2+4//4)=0.5
iL(t)=3/2+(2-3/2)e^-t/Ï=3/2+1/2e^-2t A
uL(t)=Ldi/dt=-2e^-2t V
设éååçµè·¯ç»ç¹çµå为u(t)
u(t)=2iL(t)+uL(t)=2(3/2+1/2e^-2t)-2e^-2t=3-e^-2t V
i1(t)=[12-u(t)]/4=(12-3+e^-2t )/4=9/4+1/4e^-2t A
解æ¯ã