C语言哪个函数可以测定字符串的长度

Question

如题所述

Answer 1

C语言中，计算字符串长度的函数为strlen。
1 形式：
int strlen(const char *s);
2 头文件：
string.h
3 功能:
计算字符串s的长度，并返回。

Answer 2

用sizeof函数，得到字节大小，然后看这个数组什么类型的，比如double类型，一个就占16位，就是2字节，就算出来了。
c++直接有length函数，可以直接给出长度，c没有
满意请采纳，如有疑问请追问

Answer 3

Example
/* STRLEN.C */

#include <string.h>
#include <stdio.h>
#include <conio.h>
#include <dos.h>

void main( void )
{
char buffer[61] = "How long am I?";
int len;
len = strlen( buffer );
printf( "'%s' is %d characters long\n", buffer, len );
}

Output
'How long am I?' is 14 characters long

/////////////////////////////////////////////////////////

CString::GetLength
int GetLength( ) const;

Return Value

A count of the bytes in the string.

Remarks

Call this member function to get a count of the bytes in this CString object. The count does not include a null terminator.

For multibyte character sets (MBCS), GetLength counts each 8-bit character; that is, a lead and trail byte in one multibyte character are counted as two bytes.

Example

The following example demonstrates the use of CString::GetLength.

// example for CString::GetLength
CString s( "abcdef" );
ASSERT( s.GetLength() == 6 );本回答被提问者采纳

Answer 4

int strlen(const char *s) ,s为待求长度的字符串指针，头文件string.h

Answer 5

头文件string.h
strlen(char str[]) ,str[]为待求长度的字符串