第1个回答 2009-01-19
n(Zn) = 26/65 = 0.4 mol
n(HNO3) = 63/63 = 1 mol
n(Zn) : n(HNO3) = 0.4 : 1 = 2 : 5
则方程式为:
2Zn + 5HNO3(稀) = 2Zn(NO3)2 + NxOy + (2.5)H2O
N数目守恒: x=1
O数目守恒: y=15-12-2.5 = 0.5
x:y = 1:0.5 = 2:1
生成的还原产物是N2O, 式量是 (B) 44.
4Zn + 10HNO3(稀) = 4Zn(NO3)2 + N2O + 5H2O