python输出1到100的偶数之和用函数

Question

如题所述

Answer 1

代码如下：

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def even_sum(num):
result = 0
for i in range(1,num + 1):
if i % 2 == 0:
result+= i
return  result

print(even_sum(100))

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更简便的方法是使用列表推导 一行代码就行：

print(sum([i for i in range(0,101,2 )]))

Answer 2

def fun():
res = 0

for i in range(1, 101):

if i % 2 == 0:

res += i
return res

print(fun())