从键盘输入20个字符到数组，统计其中的英文字符空格字符数字字符及其

Question

他字符的个数，并将统计结果输出。

Answer 1

#include<stdio.h>
void main()
{ char a[256];
int i,n1,n2,n3,n4;
gets(a);
for ( i=n1=n2=n3=n40;i<20;i++ )
if ( a[i]==' ' ) n1++;
else if ( (a[i]>='0')&&(a[i]<='9') ) n2++;
else if ( (a[i]>='a' && a[i]<='z')||(a[i]>='A' && a[i]<='Z') ) n3++;
else n4++;
printf("英文字符个数%d，空格数%d，数字字符个数%d，其他字符%d\n",n3,n1,n2,n4);
}

Answer 2

class Program
{
static void Main(string[] args)
{
string[] temp = new string[20];
for (int i = 0; i < temp.Length; i++)
{
temp[i] = Console.ReadLine();
}
int letter = 0;
int number = 0;
int space = 0;
int more = 0;
foreach (string str in temp)
{
if (Regex.IsMatch(str, "[a-zA-Z]")) {
letter += 1;
}
else if (Regex.IsMatch(str,"[0-9]"))
{
number += 1;
}
else if (Regex.IsMatch(str," "))
{
space += 1;
}
else
{
more += 1;
}
}
Console.WriteLine("英文字符：{0}个，空格字符：{1}个，数字字符：{2}个，其他字符：{3}个",
letter,space,number,more);
Console.ReadKey();
}
}

Answer 3

#include<stdio.h>
void
main()
{
char
a[256];
int
i,n1,n2,n3,n4;
gets(a);
for
(
i=n1=n2=n3=n40;i<20;i++
)
if
(
a[i]=='
'
)
n1++;
else
if
(
(a[i]>='0')&&(a[i]<='9')
)
n2++;
else
if
(
(a[i]>='a'
&&
a[i]<='z')||(a[i]>='A'
&&
a[i]<='Z')
)
n3++;
else
n4++;
printf("英文字符个数%d，空格数%d，数字字符个数%d，其他字符%d\n",n3,n1,n2,n4);
}