A(2pa^2,2pa),B(2pb^2,-2pb)
k(OA)*k(OB)=-1
(2pa/2pa^2)*(-2pb/2pb^2)=-1
ab=1
1,
xA*xB=2pa^2*2pb^2=4p^2
yA*yB=2pa*2pb=4p^2
2,
k(AB)=1/(a-b)
AB:y-2pa=[1/(a-b)]*(x-2pa^2)
y=(x-2p)/(a-b)
x=2p,y=0
AB必过M(2p,0)
3,题目不清楚,而且没有分,搞那么多问是没有人回答的,没有分,以后就一问即可
4,
a=b=1
A(2p,2p),B(2p,-2p)
s(min)=(1/2)*2p*(2p+2p)=4p^2
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