1.
(7x+3)å¹³æ¹-2(7x+3)=0
(7x+3)ï¼7x+3-2ï¼=0
(7x+3)(7x+1)=0
x=-3/7æx=-1/7
2.
xå¹³æ¹-7x+12-48+20x-2xå¹³æ¹=0
-xå¹³æ¹+13x-36=0
xå¹³æ¹-13x+36=0
(x-4)(x-9)=0
x=4æx=9
(7x+3)å¹³æ¹-2(7x+3)=0
(7x+3)ï¼7x+3-2ï¼=0
(7x+3)(7x+1)=0
x=-3/7æx=-1/7
2.
xå¹³æ¹-7x+12-48+20x-2xå¹³æ¹=0
-xå¹³æ¹+13x-36=0
xå¹³æ¹-13x+36=0
(x-4)(x-9)=0
x=4æx=9
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第1个回答 2014-09-01
（7X+3)^2=14x+6
(7x+3)^2-2(7x+3)=0
(7x+3)[7x+3-2]=0
7x+3=0,x=-3/7
7x+3-2=0,x=-1/7
(3-x)(4-x)=48-20x+2x^2
(x-4)(x-3)=2(24-10x+x^2)
(x-4)(x-3)-2(x-4)(x-6)=0
(x-4)(x-3-2x+12)=0
(x-4)(-x+9)=0
x=4,x=9
望采纳！！谢谢
(7x+3)^2-2(7x+3)=0
(7x+3)[7x+3-2]=0
7x+3=0,x=-3/7
7x+3-2=0,x=-1/7
(3-x)(4-x)=48-20x+2x^2
(x-4)(x-3)=2(24-10x+x^2)
(x-4)(x-3)-2(x-4)(x-6)=0
(x-4)(x-3-2x+12)=0
(x-4)(-x+9)=0
x=4,x=9
望采纳！！谢谢
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