在c++中如何通过for循环计算1+1/2+...+1/100

Question

如题所述

Answer 1

#include <stdio.h>
int main()
{
double x,sum=0;

for (x=1;x<=100;x++)

{
sum+=1/x;

}

printf("%lf\n",sum);
return 0;

}
就这个代码，复制即可，望采纳

Answer 2

C++代码，前面那个是C的

#include <iostream>
using namespace std;
int main()
{
double x,sum=0;

for (x=1;x<=100;x++)

{
sum+=1/x;
}

cout << "The result is: " << sum << endl;
return 0;

}

Answer 3

double sum=0.0;
for (i=1;i<=100;i++)
{sum+=sum+1.0/i;}