设三个年龄分别是X、Y、Z
根据条件得:
(x+y)/2+z=47
z=47-(x+y)/2
③2z=94-(x+y)
(x+z)/2+y=61
y=61-(x+z)/2
② 2y=122-(x+z)
(y+z)/2+x=60
x=60-(y+z)/2
① 2x=120-(y+z)
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得
①2x=120-(y+z)
②2y=122-(x+z)
③2z=94-(x+y)
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将①②式代入③中得
4z=188-[120-(y+z)+122-(x+z)]
4z=188-120-122+y+x+2z
2z=y+x-54
2z+54=x+y
得
④x+y=2z+54
④代入③得
2z=94-2z-54
4z=40
z=10
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将②③式代入①中得
4x=240-[122-(x+z)+94-(x+y)]
4x=240-(122+94-x-z-x-y)
4x=240-216+2x+z+y
2x=z+y+24
2x-24=z+y
得:
⑤z+y=2x-24
⑤代入①得:
2x=120-2x+24
4x=144
x=36
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将X、Y值代入①中得:
2*36=120-(y+10)
72=120-y-10
y=110-72
y=38
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X=36
Y=38
Z=10
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最大年龄38
最小年龄10
差是:28
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