(1)根据竖式可得B×A的末尾是4,B×B的末尾是4,因为2×2=4,8×8=64,可得B是2或8;
假设B=2,2×7=14,可得A=7,又72×7=504,与114不符,所以B是8;
又因为8×3=24,可得A=3;那么AB是38,BA是83,38×83=3154;
由以上可得竖式:
![](https://video.ask-data.xyz/img.php?b=https://iknow-pic.cdn.bcebos.com/e824b899a9014c08e4bc8c14097b02087af4f4f8?x-bce-process=image%2Fresize%2Cm_lfit%2Cw_600%2Ch_800%2Climit_1%2Fquality%2Cq_85%2Fformat%2Cf_auto)
;
(2)根据竖式可得,AB×2=74,所以AB=74÷2=37,因此A=3,B=7;
7×D的末尾是D,7×0=0,7×5=35,显然0不符合,那么D只能是5,又37×5=185可得:E=1,C=8;
由以上可得竖式:
![](https://video.ask-data.xyz/img.php?b=https://iknow-pic.cdn.bcebos.com/c2fdfc039245d6887cb1a426a7c27d1ed31b2484?x-bce-process=image%2Fresize%2Cm_lfit%2Cw_600%2Ch_800%2Climit_1%2Fquality%2Cq_85%2Fformat%2Cf_auto)
;
(3)根据竖式可得:个位上一定有进位,假设个位上向十位上进1,十位上“加”+“加”+1的末尾是0,那么A得不出整数;
假设个位上向十位上进2,十位上“加”+“加”+2的末尾是0,由4+4+2=10,9+9+2=20;可得“加”是4或9;
假设“加”是4,4+3ד鞭”=24,那么“鞭”不是整数;因此“加”只能是9;9+3ד鞭”=24,可得“鞭”=5;
十位上:9+9+2=20,向百位上进2;
百位上:“马”+2的末尾是0,由8+2=10,可得:“马”=8,向千位上进1;
千位上:“快”+1=2,那么“快”=1;
由以上可得竖式:
![](https://video.ask-data.xyz/img.php?b=https://iknow-pic.cdn.bcebos.com/77c6a7efce1b9d1695a78ce3f0deb48f8d5464cb?x-bce-process=image%2Fresize%2Cm_lfit%2Cw_600%2Ch_800%2Climit_1%2Fquality%2Cq_85%2Fformat%2Cf_auto)
;
(4)由竖式可得:“真”=1;
个位上:3ד乐”的末尾是4,由3×8=24可得“乐”=8,向十位上进2;
十位上:3ד快”+2的末尾是0,也就是3ד快”的末尾是8,由3×6=18可得“快”=6,3×6+2=20,向百位上进行2;
百位上:1+“是”+2的末尾是0,由1+7+2=10可得“是”=7;
由以上可得竖式:
![](https://video.ask-data.xyz/img.php?b=https://iknow-pic.cdn.bcebos.com/3812b31bb051f819639615c8d9b44aed2f73e785?x-bce-process=image%2Fresize%2Cm_lfit%2Cw_600%2Ch_800%2Climit_1%2Fquality%2Cq_85%2Fformat%2Cf_auto)
.