八年级数学化简题

Question

描述不清楚 还是看图吧。

Answer 1

{[x(x+1)-x]/x(x-2)}[(x^2-4]/x]
=[x^2/x(x-2)][(x+2)(x-2)]/x]
=x+2

Answer 2

x+2

Answer 3

原式=[x(x+1)-x]/x(x-2)*（x^2-4)/x
=X^2/x(x-2)*(x^2-4)/x
=x+2

Answer 4

x(x+1)-x x2+4 x(x+1-1) (x+2)(x-2)
------------ ------------- = ------------- ------------- =x+2
x(x-2) x x(x-2) x

Answer 5

先因式分解，再通分，过程如下：
[（x+1）/（x-2）-x/（x^2-2x）]（x-4/x)
=[（x+1）/（x-2）-x/x（x-2）]（x-4/x)
=[（x+1）/（x-2）-1/(x-2)]（x-4/x)
={[（x+1）-1]/(x-2)}（x-4/x)
=[x/(x-2)]（x-4/x)
=[x/(x-2)]（x^2-4)/x
=[x/(x-2)]（x^2-4)/x
=[x/(x-2)]（x+2)(x-2)/x

把分子分母写到一起
[x/(x-2)]（x+2)(x-2)/x
=x（x+2）（x-2）/[(x-2)x]
=x+2