#include <stdio.h>
#include <string.h>
#include <ctype.h>
#include <stdlib.h>
#define MAX_LONG 5 // 假设只有5个数字
void main(void)
{
unsigned int digits[100];
char target[]="70112"; // 这里是你的目标数字(当然你也可改为其它的5个数字)
char dest[12];
int start=-1,i,j,k,len,sum,OddNumber,EvenNumber;
i=j=k=len=OddNumber=EvenNumber=sum=0;
while (target[i])
{
start=i;
len=1;
strncpy(dest,&target[start],len);
dest[len]='\0';
digits[j]=atoi(dest);
j++;
start=-1;
i++;
}
for (k=0;k<MAX_LONG;k++)
{
sum+=digits[k]; //5数之和
if(digits[k]%2==0) EvenNumber+=digits[k]; // 偶数求和
else OddNumber+=digits[k]; // 奇数求和
}
printf("五数之和:%d\n奇数之和:%d\n偶数之和:%d\n",sum,OddNumber,EvenNumber);
}
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