x的平方+2xy+y的平方+x+y-2，请因式分解

Question

有过程

Answer 1

原式=(x²-2xy+y²)+(x-y)
=(x-y)²+(x-y)
=(x-y)(x-y+1)

Answer 2

解:x的平方+2xy+y的平方+x+y-2
x^2+2xy+y^2+x+y-2
=(X+Y)^2+(X+Y)-2
=(X+Y+2)(X+Y-1)

Answer 3

=(X+Y)^2+(X+Y)-2
=(X+Y+2)(X+Y-1)本回答被提问者采纳

Answer 4

(X+Y)^2+(X+Y)-2
(X+Y+2)(X+Y-1)

Answer 5

1 1 2
1 1 -1
(x+y+2)(x+y-1)