如题所述
证明:
∵等边△ABC
∴BC = AC
∵BD是ABC的角平分线
∴∠DBC = ∠BCA/2
∵CE = BC/2
∴CE = AC/2 = CD
∴∠E = ∠CDE
∵∠BCA = ∠E+∠CDE = 2∠E
∴∠E = ∠DBC 请采纳