计算(x-1)(x-2)(x-3)(x-4)

Question

适合初二年级，越简单越好，要过程！

Answer 1

(x-1)(x-2)(x-3)(x-4)
=[(x-1)(x-4)][(x-2)(x-3)]
=(x^2-5x+4)(x^2-5x+6)
=[(x^2-5x+5)-1][(x^2-5x+5)+1]
=(x^2-5x+5)^2-1^2
=x^4+25x^2+25-10x^3+10x^2-50x-1
=x^4-10x^3+35x^2-50x+24.

Answer 2

(x-1)(x-2)(x-3)(x-4)
=[(x-1)(x-4)][(x-2)(x-3)]
=(x^2-5x+4)(x^2-5x+6)
=[(x^2-5x+5)-1][(x^2-5x+5)+1]
=(x^2-5x+5)^2-1^2
=x^4+25x^2+25-10x^3+10x^2-50x-1
=x^4-10x^3+35x^2-50x+24.
(x^？是x的？次方）

Answer 3

原式=(x-1)(x-4)(x-2)(x-3)
=(x^2-5x+4)(x^2-5x+6)
=x^4-5x^3+6x^2-5x^3+25x^2-30x+4x^2-20x+24
=x^4-10x^3+35x^2-50x+24本回答被提问者采纳

Answer 4

原式=(x-1)(x-4)(x-2)(x-3)
=(x^2-5x+4)(x^2-5x+6)
=(x^2-5x)^2+10(x^2-5x)+24
接下来自己算吧

Answer 5

原式=(x-1)(x-4)(x-2)(x-3)
=(x^2-5x+4)(x^2-5x+6)
=(x^2-5x)^2+10(x^2-5x)+24