一直直线y=x+3的图像与x,y轴的交于A、B两点，直线L经过原点与线段AB交于点C，把三角形AOB的面积

Question

一直直线y=x+3的图像与x,y轴的交于A、B两点，直线L经过原点与线段AB交于点C，把三角形AOB的面积分成2：1两部分。求直线L的解析式。

Answer 1

y=x+3的图像与x,y轴的交于A、B两点,A、B两点坐标为（-3，0）（0，3）直线L经过原点与线段AB交于点C，把三角形AOB的面积分成2：1两部分，若S△AOC=2S△BOC,则C坐标为(-1,2)
L的解析式为y=-2x

若S△AOC=1/2S△BOC,则C坐标为(-2,1)
L的解析式为y=-1/2x

Answer 2

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