第2个回答 2015-01-06
trunc(125.815) would return 125
trunc(125.815, 0) would return 125
trunc(125.815, 1) would return 125.8
trunc(125.815, 2) would return 125.81
trunc(125.815, 3) would return 125.815
trunc(-125.815, 2) would return -125.81
trunc(125.815, -1) would return 120
trunc(125.815, -2) would return 100
trunc(125.815, -3) would return 0
第3个回答 2015-01-06
substring(ID,1,(charindex('.',ID)-1)
从ID第一位开始截取 到 ‘.’前面的值