实现一个给定的二维数组（M*N）的转置（行列互换）的c++程序怎么编

Question

如题所述

Answer 1

#include <iostream> //转置数组
using namespace std;
#define SIZE 100
void main()
{
int arr1[SIZE][SIZE];
int arr2[SIZE][SIZE];
int m, n, i, j;
cout << "输入M N：";
cin >> m >> n;
for (i = 0; i != m; ++i)
{
for (j = 0; j != n; ++j)
{
cin >> arr1[i][j];
}
}
cout << "转置前：" << endl;
for (i = 0; i != m; ++i)
{
for (j = 0; j != n; ++j)
{
cout << arr1[i][j] << " ";
arr2[j][i] = arr1[i][j];
}
cout << endl;
}
cout << "转置后：" << endl;;
for (i = 0; i != n; ++i)
{
for (j = 0; j != m; ++j)
{
cout << arr2[i][j] << " ";
}
cout << endl;
}
}追问

你好，请问，size 100，是什么意思，为什么要加这个

追答

define 是宏定义啊，定义size的大小为100