如何从现有的一维数组中随机抽取一个数(C#)

Question

如题所述

Answer 1

//定义一个数组,用来产生随机数（一位数组你可以自己定义，我这里定义一个字符数组）
private static char[] constant =
{
'0','1','2','3','4','5','6','7','8','9',
'a','b','c','d','e','f','g','h','i','j','k','l','m','n','o','p','q','r','s','t','u','v','w','x','y','z',
'A','B','C','D','E','F','G','H','I','J','K','L','M','N','O','P','Q','R','S','T','U','V','W','X','Y','Z'
};

//随机方法,传入需要的长度,返回一个随机生成的字符串，参数控制你抽取的长度
public static string GenerateRandom(int Length)
{
System.Text.StringBuilder newRandom = new System.Text.StringBuilder(52);
Random rd = new Random();
for (int i = 0; i < Length; i++)
{
newRandom.Append(constant[rd.Next(52)]);
}
return newRandom.ToString();
}

还有什么问题，你可以再联系我~

Answer 2

string[] strs = { "111","222","333"};
Random rand = new Random(System.Guid.NewGuid().GetHashCode());
Console.Write(strs[rand.Next(0, strs.Length)]);

参考资料：http://www.0qf.net