c语言中怎样正确输出双长整形变量

Question

#include<stdio.h>

void main(){
unsigned long long i;
i=184467440737065520;
printf("%d", sizeof(i));
printf("\n%d", i);

}

Answer 1

printf("%llu",i);
即可输出unsigned long long 的变量
printf("%lld",i);
输出long long型变量

Answer 2

用%lld，如下
#include<stdio.h>

void main(){
unsigned long long i;
i=184467440737065520;
printf("%d", sizeof(i));
printf("\n%lld", i);

}本回答被提问者采纳

Answer 3

printf("%ld")

Answer 4

#include<stdio.h>

void main(){
unsigned long long i;
i=184467440737065520;
printf("%d", sizeof(i));
printf("\n%lld", i);

}

Answer 5

用%lld。
内容为：

void main(){
unsigned long long i;
i=184467440737065520;
printf("%d", sizeof(i));
printf("\n%lld", i);