已知a≠0,b≠0,且1a+1b=4,那么4a+3ab+4b?3a+2ab?3b=?1910?1910

已知a≠0,b≠0,且1a+1b=4,那么4a+3ab+4b?3a+2ab?3b=?1910?1910.

1
a
+
1
b
=4,
∴a+b=4ab,
4a+3ab+4b
?3a+2ab?3b
=
4(a+b)+3ab
?3(a+b)+2ab
=
19ab
?10ab
=?
19
10

故答案为-
19
10
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