第1个回答 2020-10-25
解如下图所示
第2个回答 2020-10-25
√(n²+1)π=[√(n²+1)-n]π+nπ=π/[√(n²+1)+n]+nπ。
∴原式=lim(n→∞)[(-1)^n]sin{π/[√(n²+1)+n]}=0。
供参考。
∴原式=lim(n→∞)[(-1)^n]sin{π/[√(n²+1)+n]}=0。
供参考。
第3个回答 2020-10-25
1%E3%80%81%E8%AE%BE%E5%B9%B3%E9%9D%A2%E7%9A%84%E6%88%AA%E8%B7%9D%E5%BC%8F%E6%96%B9%E7%A8%8B%E6%98%AFx%2F3%EF%BC%8By%2Fb%EF%BC%8Bz%2F1%EF%BC%9D1%EF%BC%8C%E5%88%99%E5%B9%B3%E9%9D%A2%E7%9A%84%E6%B3%95%E5%90%91%E9%87%8F%E6%98%AF%281%2F3%2C1%2Fb%2C1%29%20xoy%E9%9D%A2%E7%9A%84%E6%B3%95%E5%90%91%E9%87%8F%E6%98%AF%280%2C0%2C1%29%EF%BC%8C%E6%89%80%E4%BB%A5%20cos%EF%BC%88%CF%80%2F3%EF%BC%89%EF%BC%9D1%2F%E2%88%9A%5B1%2F9%EF%BC%8B1%2Fb%5E2%EF%BC%8B1%5D%EF%BC%8C%E5%BE%97b%EF%BC%9D%C2%B13%2F%E2%88%9A%2826%29%20%E6%89%80%E4%BB%A5%EF%BC%8C%E5%B9%B3%E9%9D%A2%E6%96%B9%E7%A8%8B%E6%98%AFx%2F3%EF%BC%8B%E2%88%9A%2826%29y%2F3%EF%BC%8Bz%2F1%EF%BC%9D1%E6%88%96x%2F3%EF%BC%8D%E2%88%9A%2826%29y%2F3%EF%BC%8Bz%2F1%EF%BC%9D1%EF%BC%8C%E4%B9%9F%E5%8F%AF%E4%BB%A5%E6%8A%8A%E5%B9%B3%E9%9D%A2%E6%96%B9%E7%A8%8B%E5%86%99%E6%88%90x%EF%BC%8B%E2%88%9A%2826%29y%EF%BC%8B3z%EF%BC%8D3%EF%BC%9D0%E6%88%96x%EF%BC%8D%E2%88%9A%2826%29y%EF%BC%8B3z%EF%BC%8D3%EF%BC%9D0%202%E3%80%81tany%2Fx%E6%98%AFtan%28y%2Fx%29%E7%9A%84%E6%84%8F%E6%80%9D%E5%90%A7%EF%BC%9F%20%E8%BF%99%E4%B8%AA%E4%B8%80%E4%B8%AA%E9%BD%90%E6%AC%A1%E6%96%B9%E7%A8%8B%EF%BC%8C%E8%AE%BEu%EF%BC%9Dy%2Fx%EF%BC%8C%E5%88%99dy%2Fdx%EF%BC%9Du%EF%BC%8Bx%2Adu%2Fdx%EF%BC%8C%E6%89%80%E4%BB%A5%E5%8E%9F%E6%96%B9%E7%A8%8B%E5%8C%96%E4%B8%BAu%EF%BC%8Bxu%26%2339%3B%EF%BC%9Du%EF%BC%8Btanu%EF%BC%8C%E5%8D%B3xu%26%2339%3B%EF%BC%9Dtanu%20%E5%88%86%E7%A6%BB%E5%8F%98%E9%87%8F%EF%BC%9Acotudu%EF%BC%9Ddx%2Fx%20%E4%B8%A4%E8%BE%B9%E7%A7%AF%E5%88%86%EF%BC%9Alnsinu%EF%BC%9Dlnx%EF%BC%8Blnc%20%E5%BE%97sinu%EF%BC%9Dcx%EF%BC%8C%E4%BB%A3%E5%85%A5u%EF%BC%9Dy%2Fx%E5%BE%97%E5%8E%9F%E6%96%B9%E7%A8%8B%E7%9A%84%E9%80%9A%E8%A7%A3sin%28y%2Fx%29%EF%BC%9Dcx
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