用因式分解法解下列方程,过程详细一点
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第1个回答 2014-09-23
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追答求采纳哦~
第4个回答 2014-09-23
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用因式分解法解下列方程答:1,解:3(x-5)^2=2(5-x)(x-5)[3(x-5)+2)=0 (x-5)(3x-13)=0,x1=5,x2=13/3,2,解.(2x-1)(x+1)=(3x+1)(x+1)(x+1)(x+2)=0,∴x1=-1,x2=-2 3,解.(x-2)(x-5)=70 x^2-7x+10=70 x^2-7x-60=0 (x+5)(x-12)=0,x1=-5,x2=12 4,解 ...