3(x-4)平方=2x-8 {ps:(x-4)平方为(x-4)^2}
=> 3(x-4)(x-4)=2(x-4)
=> 3(x-4)(x-4)-2(x-4)=0
=> (x-4)(3x-12-2)=0
=> (x-4)(3x-14)=0
=> x=4或14/3
(x-根号3)平方=5(根号3-x)
=> (x-根号3)(x-根号3)=5(根号3-x)
=> (x-根号3)(x-根号3)-5(根号3-x)=0
=> (x-根号3)(x-根号3-5)=0
=> x=根号3或根号3+5
(x-1)(x+3)=12
=> x^2+2x-3=12
=> x^2+2x-15=0
=> (x-3)(x+5)=0
=> x=3或-5
(2x-1)平方+3(2x-1)+2=0
=> ((2x-1)+1)((2x-1)+2)=0
=> 2x(2x+1)=0
=> x=2或x=-1/2
追问谢谢回答,但是好像答案有点儿不对
追答那个答案有点不对?