楼ä¸ç¬¬1é¢å®å
¨æ²¡æçå°é®é¢çæ¬è´¨ï¼æ¢å
ï¼æ
åçæ为麻ç¦ã
解ï¼
1. åå½¢ï¼å°x^2-xçä½æ´ä½ï¼è®¾ä¸ºtãé£ä¹
ï¼x^2-xï¼^2-4(2x^2-2x-3)=t^2-4(2t-3)=t^2-8t+12=(t-2)(t-6)ã
å æ¤
ï¼x^2-xï¼^2-4(2x^2-2x-3)=(x^2-x-2)(x^2-x-6)
=(x-2)(x+1)(x-3)(x+2)
æ以å¯å°æ¹ç¨å形为(x-2)(x+1)(x-3)(x+2)ã
容æå¾ç¥æ¹ç¨ç解为x1=-2,x2=-1,x3=2,x4=3ã
2. ç±äº
ax(a-x)-ab^2=b(b^2-x^2),
æ以
a^2x-ax^2-ab^2=b^3-bx^2.
å³(a-b)x^2-a^2x+ab^2+b^3.
å解å å¼ï¼å¾å°ï¼[(a-b)x-b^2](x-a-b)=0.
åå 为a-bä¸çäº0ï¼
å æ¤åæ¹ç¨ç解为x1=b^2/(a-b),x2=a+bã
3. ç±äºabx^2-(a^2+b^2)x+ab=0
å解å å¼å¾å°ï¼
(ax-b)(bx-a)=0.
åå 为abä¸çäº0ï¼
æ
åæ¹ç¨ç解为x1=a/b,x2=b/aã
温馨提示:答案为网友推荐,仅供参考