第1个回答 2014-08-14
1)移项:2(5x-1)^2-2(5x-1)=0
提取公因式:2(5x-1)(5x-1-1)=0
2(5x-1)(5x-2)=0
x=1/5, 2/5
2)7x(x-2)+3(x-2)=0
(x-2)(7x+3)=0
x=2, -3/7
第2个回答 2014-08-14
(1)2(5x-1)²=2(5x-1)
2(5x-1)²-2(5x-1)=0
2(5x-1)*(5x-1-1)=0
2(5x-1)*(5x-2)=0
所以5x-1=0或者5x-2=0
解得x=1/5或2/5
(2)原式移项得7x(x-2)+3(x-2)=0
(x-2)(7x+3)=0
所以x-2=0或7x+3=0
解得x=2或x=-3/7
第3个回答 2014-08-14
(1) 移项:2(5x-1)²-2(5x-1)=0
合并同类项:2(5x-1)(5x-2)=0
∴ x1=5分之1, x2=5分之2
(2)移项:7x(2-x)-3(x-2)=0
合并同类项:(7x+3)(2-x)=0
∴ x1= - 7分之3, x2=2